7(2x+1)^2+20(2x+1)=3

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Solution for 7(2x+1)^2+20(2x+1)=3 equation: 



7(2x+1)^2+20(2x+1)=3

We move all terms to the left:

7(2x+1)^2+20(2x+1)-(3)=0

We multiply parentheses

7(2x+1)^2+40x+20-3=0

We add all the numbers together, and all the variables

40x+7(2x+1)^2+17=0

We move all terms containing x to the left, all other terms to the right

40x+7(2x+1)^2=-17

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